$\sec^2x+\left(\frac{1}{2}\right)\tan\left(x\right)-1=0$
$45\:.\:25\:.\:0,0390625\:$
$y\cdot\cos\left(x^2\right)\cdot y$
$\left(2x+3\right)\cdot\:\left(2x+10\right)$
$1+2\sec^2\left(x\right)\cdot\tan^2\left(x\right)-\tan^4\left(x\right)$
$\int\left(-4x^3+5x^2\right)\sin2xdx$
$6.14-27$
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