$\frac{s+5}{12}=5$
$3x^2-3x+8$
$-2x+10\le20$
$\lim_{x\to\infty}\frac{3x^2-8x}{3\left(x^3-4x^2\right)^{\frac{2}{3}}}-1$
$\frac{x^5-32}{x+2}$
$\frac{14}{2}-5$
$\frac{1}{\sec\left(y-1\right)}+\frac{1}{\sec\left(y+1\right)}$
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