$-10x^3y^2\left(9x\right)$
$\frac{36}{3x^2}$
$\sec+\tan=\frac{\cos}{1+\sin}$
$3x^2-18x+35$
$\lim_{x\to0}\left(\frac{1}{\left(tan\left(x\right)^{-1}\right)^2}\right)$
$\int\frac{x}{\sqrt{19+18x-x^2}}dx$
$\left(\left(-3\cdot8\right)-\left(-3\cdot8\right)\right)+9$
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