$\frac{4x-2+3x+3}{6}$
$p\left(3\right)=3^2-3x+1$
$\frac{\left(-x^2+3x+28\right)}{\left(4+x\right)}$
$\left(2x^3+5x-3\right)+\left(4x-3x^2+2\right)$
$39\cdot24$
$\left|7\left(1\right)-2\right|$
$10\cdot 57$
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