$\int\frac{1+3s^4+5s^3}{s\left(s^4-1\right)}ds$
$200mn^3-50mn^2$
$\left(3a^2b^2\right)\left(a^2b^8-8ab\right)$
$2\cdot5-4+1-3$
$3^2\cdot3^5\cdot3\cdot3^{-3}$
$\frac{\left(ab^{4}c^{-3}\right)^{-5}}{\left(a^{4}b^{4}c^{5}\right)^{5}}$
$4x^2-5x+7$
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