$\left(\frac{3}{5}x^2\right)\left(10x^4-20x^3-40x^2+15x+5\right)$
$\frac{dy}{dx}=2x,\:y\left(1\right)=7$
$2x+3\le-9$
$\left(1-cos^2\theta\right)\left(1+cot^2\theta\right)=1$
$10b-30ab^2$
$\ln\left(2x+3\right)+\ln x=\ln\left(1+4x\right)$
$\frac{5a^{3}+2a^{2}-3}{a^{2}}$
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