$\frac{dy}{dx}\left(xy^4=5\right)$
$x^2-4x\:-8y-12=0$
$\lim_{x\to0\:}\left(\frac{e^{10x}-1}{x}\right)$
$16\:sin\left(4x\right)cos\left(4x\right)cos\left(8x\right)$
$-2x^4\cdot6x^3$
$\frac{dy}{dx}=\frac{e^{-y}+e^{-6x-y}}{e^xy}$
$\frac{8yx^3}{-4x^4}\:$
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