$\left(4n^3+9x^5\right)^2$
$\lim_{x\to0}\left(\frac{sin\left(x\right)tan\left(2x\right)}{1-cos\left(x\right)}\right)$
$-3\left(-1.25\right)$
$7x+30\ge-8$
$\frac{10x^{12}}{2x^4}$
$\int\left(12\tan\left(2x\right)^5\right)dx$
$0t-9t+6u+4u^5$
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