$\left(3x-y\right)\left(a+3b\right)$
$\left(6a+b-c\right)^2$
$-10+\left(-4\right)\left(-10\right)$
$\left(1-a\right)+\left(a+1\right)$
$\int\frac{x}{\left(u\right)^3}dx$
$9r-17=19$
$\left(\:\frac{3a}{b}+2\right)\:\left(\:\frac{3a}{b}-6\right)$
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