$\int\:12x^3\left(x^4+1\right)^9dx$
$3x^2+6-1$
$\frac{\frac{1}{x+4}-\frac{1}{4}}{x}$
$\left(-2\cdot t-4\cdot m+y\right)^2$
$\left(3x+2\right)^4\left(8x-9\right)^2$
$z\left(8\right)q\left(2\right)$
$\left(-9\right)\left(2\right)\left(-2\right)$
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