$8x^7-18x$
$\frac{x^2+3x+9}{2x-2}$
$\frac{2}{\sin\left(x\right)}=\frac{\sin\left(x\right)}{1+\cos\left(x\right)}+\frac{\sin\left(x\right)}{1-\cos\left(x\right)}$
$2x+y=40$
$-8\frac{1}{2}^3$
$18-3\cdot2+3-1$
$25x^2-10x\:+\:1$
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