$\int\frac{x^2\:-x\:+\:18}{x^3+3x}dx$

$\sqrt{\left(2+3x-2x^2\right)}$

$h\:+11=\:83$

$-\frac{1}{3}+\frac{4}{3}$

$\lim_{x\to0}2\left(x+y\right)^2-4\left(x+y\right)-\left(2x^2-4x\right)$

$\frac{dy}{dx}=10x-12x^3$

$\frac{d}{dx}\left(xy+arctan\left(\frac{x}{y}\right)\right)$