$\frac{1}{4}\int\frac{1}{1+\frac{u^2}{4}}du$
$\left(10a^2-4a^7\right)^2$
$4c\:+\:2c\:+\:3$
$x+2y\left(3\right)$
$y^2-6y>-10$
$0.002\cdot0.10000^2$
$\left(3x-2y\right)^2\:$
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