$1+x+y^2+xy^2$
$\left(-6x^4+8y^3\right)^2$
$x^4+2x^3-5x^2$
$\int255-t^2dt$
$3\left(4x+8\right)+3\left(2x-6\right)$
$4.64\cdot30$
$\frac{3}{2}\left(x+y\right)-\frac{5}{4}y=\frac{1}{2}\left(y+2\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!