$40-\left(-3\right)$
$x^3-xy^2=3xy$
$\frac{-4+9\cdot2}{7\cdot2}$
$\left(\frac{1}{4}x-\frac{4}{3}y\right)\left(\frac{1}{4}x+\frac{4}{3}y\right)$
$5e^{6x+3}=0$
$125x^3-1$
$16v^2+24v+9$
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