$\left(ln\infty\right)^2$

$x^2-3x-10=10$

$y'=\frac{2x}{1+2y}$

$\frac{2}{3}\cdot\:\left(-5x^4y^2+3xy^2-6x^2y\right)$

$\int\frac{\sqrt{x^2+3}}{5x}dx$

$\frac{3x^3-8^2+9x-10}{x-2}$

$\frac{\sqrt[5]{\sqrt[3]{w^{30}g^{-90}}}}{\sqrt[3]{\sqrt[5]{w^{15}\cdota^{-120}}}}\cdot\sqrt[15]{-32768}$