$\int\:\frac{1}{\left(x-6\right)^2\left(x-3\right)}dx$
$3\left(y+1\right)$
$\lim_{x\to0}\left(\frac{\left(x^2-36\right)\left(x-6\right)}{x^2-12x+36}\right)$
$\int x^3log\:xdx$
$\int\frac{x^2+2x-3}{x-1}dx$
$x^2+10x+16<0$
$y=x^{-3x}$
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