$4x^2+13x+3$
$-3d\:+\:8\:-\:2d\:=\:8\:$
$x^2-7x+3x-21\ge4-4x$
$\frac{\left(1+\tan\left(x\right)\right)^2}{\sec\left(x\right)}=\sec\left(x\right)+2\sin\left(y\right)$
$x^2+4x\:=\:20$
$\lim_{x\to0}\left(\frac{x^3-8}{x^2-4}\right)$
$x^2+20x-8$
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