$\frac{2}{3}x+\frac{1}{3}=-\frac{7}{3}$
$\left(2^5\right)\left(3^9\right)$
$4\:\left(x\:-\:2\right)>8$
$2\left(3x^4y\right)^3\:$
$\int\sqrt[3]{3x+4}dx$
$\int\left(x^3e^{x^4+3}\right)dx$
$\lim_{x\to6}\left(\frac{x^2-12x-24}{x-6}\right)$
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