$24+\infty$
$\sec\left(x\right)+1=\frac{\tan^2\left(x\right)}{sec\left(x\right)-1}$
$6a^2+24xy+24y^2$
$\sqrt{\left(m+1\right)^2}$
$\int cos\:\sqrt{x-1}dx$
$\left(-5x^3\right)\cdot\left(2x^4-x^3-3x\right)$
$x^3y^3=3$
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