$\left(16u\right)\frac{3}{4}$
$a\left(x\right)=-x^2+100x$
$lim_-\left\{x\:to\:0\right\}\:\frac{\:cot\:3x\:}{cot\:x}$
$\frac{b^5+243}{b\:+\:3}$
$-4x^7-8x^3+12x^4+4x^2+16x$
$\lim_{x\to+\infty\:}\left(4\right)^x$
$-12\cdot48$
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