$\left(c+4\right)\left(c-5\right)$
$\lim_{x\to0}\ln\left(\frac{1+6x}{x}\right)$
$8\left(5-5r\right)-\left(-3-5r\right)$
$829\:+\:544$
$10a^4b^2-18a^2b^3-20ab$
$\int\left(2x^2+3\right)\cos\left(x\right)dx$
$3-5+8+6-38-25$
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