$\int\frac{\left(3x+8\right)}{9x^2-3x-1}dx$
$\int\frac{24x}{\sqrt[3]{6x^2+1}}dx$
$5x-8=32$
$8y+49=-3\left(y-9\right)$
$\int\frac{x^2+1}{3x^2-x-4}dx$
$\left(8b^6+k\right)^3$
$\int\left(\sqrt{1-6y}\right)dy$
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