$\frac{13}{3w-3}-\frac{1}{w-1}=\frac{w}{9}$
$46+\left(-5\right)^3-3x\left(-2\right)^3$
$2\:\frac{\left(\frac{1}{2}\right)}{\frac{1}{3^2}}$
$\int\:17\:dx$
$\left(\frac{1}{x}+\frac{2}{y}-\frac{3}{z}\right)^2$
$\lim_{x\to\infty}\left(-6x^3-x^2\right)$
$\left(-7\right).\left|\left(-3\right)+\left(+6\right)\right|$
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