$y=\frac{\left(x^3-1\right)^{0.5}x\left(4x+1\right)^{0.25}}{\left(x^5+3\right)^{0.2}}$
$-3x<-11$
$\int\frac{sec^2ax}{tan\:ax}dx$
$4x^2-16x^2y^2$
$\frac{x^2\cdot x^6}{x^7\cdot x^{10}}$
$\frac{x}{-12}=2$
$\left(\frac{2x^2}{y}\right)-\left(\frac{y^2}{x}\right)^{20}$
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