$740\:+\:1000$
$-9z^3\cdot3z^4$
$\lim_{x\to4}\left(x^2+5x-10\right)$
$6x^2+6x-36$
$\frac{2x+4}{3}>\frac{x}{6}$
$-10^2-10+5$
$0,\frac{3}{8}b^{2}-0,b^{3}0,b^{2}+\frac{1}{4}b^{3}\frac{2}{5}$
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