$\frac{x^5+243}{x+3}$
$4-12+9x^2$
$\left(x^3+2x+5\right)\left(3x-9\right)$
$\lim_{x\to5}\left(\frac{x^2-10x+25}{x^3-2x-15}\right)$
$\frac{1-\sin^2x}{\cot x}=\sin x\cos x$
$\frac{1}{2}\cdot\:\log\:_{27}\left(5c+6\right)=\frac{2}{3}$
$-625\cdot65$
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