$\left(5x^2y+4m\right)^3$
$tan\:x\cdot cosx=sen^2x+senx\cdot cos^2x$
$5x+3=-27$
$2x^4+18x^3+96x^2+468x+320$
$\lim_{x\to-\left(\infty\right)}\left(\frac{\left(e^x\left(x^2+4\right)\right)}{x-2}\right)$
$\int\frac{\sqrt[2]{t}+3}{t+3}dt$
$\frac{1-sen^2x}{sec^2x}\:=\:cos^2x$
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