$\int4x\left(7x-4\right)^3dx$
$b\left(x+12\right)^2-by^2$
$\left(x^2-5x-14\right)$
$\int\left(\csc\left(\frac{x}{4}\right)\right)^4dx$
$x^2+mx+4=\left(x+n\right)^2$
$1-x-x^2$
$x^2+14x+33=0$
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