$xy'+y=xy^3$
$-113\cdot4$
$\frac{x^2-3x+2}{\sqrt[3]{x^2}-\sqrt[3]{x+2}}$
$\left(-2x^2y^7z^4\right)^3$
$\frac{d}{dx}\:-4x\sqrt{x}$
$-8-5\left(-2+\left(-1\right)\left(-5\right)\right)^2-1$
$\cos^2a+\cos^2b+\cos^2c\:=\:1$
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