$100m^2n^4-\frac{1}{6}x^8$

$\left(26m-n^2\right)\left(26m+n^2\right)$

$\left(x-6^2\right)$

$\lim_{x\to\infty}\left(\frac{16x^2-3x+6}{8x^2+6x+8}\right)$

$\frac{x+1}{x^2-3x-4}$

$76+96+86+176+\left(367\right)+26$

$\left(4m^6+\:2n^8\right)\:\left(4m^6\:-\:2n^8\right)\:$