$\frac{5}{y+3}-\frac{4}{3y}=\frac{7}{y^2+3y}$

$6\tan\left(b\right)-4=2\tan\left(b\right)-9$

$\int_0^26e^{-2x}dx$

$\lim_{x\to0}\left(\frac{\cos\left(9x-\:1\right)}{x^2}\right)$

$3-\left\{4+5-\left[1-\left(-3+1\right)\right]-\left[4-2+\left(-5+3\right)-4\right]\right\}-10$

$9.9\cdot9.34$

$\int\left(6x^2+4x\right)\left(x^3+x^2\right)dx$