$6z^3+12z^2+10z$
$\frac{dy}{dx}\left(x^2+6xy+y-9\right)$
$\left(3a^3+8b^3\right)^2$
$\frac{x}{2}+\frac{x}{3}+7=x$
$121m^4-49$
$3\left(4g^2+4g+3\right)$
$\left(x^2+4x-12\right)-\left(x^3-5y+13\right)$
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