$80,000\left(5.14\right)$
$-a-a+1$
$\left(\frac{x}{4}+1\right)^3$
$\left(2x^2-xy\right)^1$
$\frac{\sec\left(x\right)+1}{\tan\left(x\right)}+\frac{-\tan\left(x\right)}{\sec\left(x\right)+1}$
$\frac{-48}{-3}$
$-4x^2-16x-36$
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