$\frac{4}{x-4}=\frac{3x}{x+3}$
$\int\left(x^2\left(r^3+4\right)^3\right)dx$
$\left(-19\right)\cdot\left(-146820\right)$
$-2\left(-4x+12y\right)$
$x^3-7x^4$
$9x^4-3x^5+11x^2$
$\int4x^3e^{4x^4}dx$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!