$\int\frac{x-3}{\left(x^2-6x+9\right)^2}dx$
$y^2-6y+1$
$x^2+4x+12$
$5x^2y+10xy+5y$
$5x\left(4x^6-y^2\right)$
$\frac{\left(22+-16\right)}{\left(-5+7\right)}$
$\frac{dy}{dx}=\frac{-5x}{6y}$
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