$\left(2x-a\right)^2$
$4^2\:x\:-8$
$\frac{\left(x^2+9\right)\left(x-8\right)}{x^2-x+1}$
$y'=\frac{2x^2+2xy-y^2}{x^2}$
$\left(7x+\frac{1}{\sqrt{3}}\right)^2$
$3\left(x^2\right)^2-\left(y\right)^2$
$16x^5+40x^3y^3+25xy^6$
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