$1+\frac{1}{x}=\frac{72}{x^2}$

$2x+3\le5$

$2x+3=7$

$\cos\left(3x\right)\sin\left(x\right)-\sin\left(3x\right)\cos\left(x\right)=1$

$\left(\frac{5}{6}a^2bc-\frac{3}{2}ab^2c\right)^2$

$\int\left(3x+1\right)\left(5x+1\right)^{0.5}dx$

$- 1 - ( - 4 + 6 ) + 2 - ( - 1 - 2 )$