$-697+-697$
$2x+41=127$
$16b^2\:-\:9$
$\left(-10x+4\right)^2$
$\left(3x^2-7x-1\right)\left(-4\right)$
$\left(mn-pq\right)^2$
$\lim_{x\to4}\left|\frac{\left(x^2-16\right)\sin\left(x-4\right)}{2x^5-5x-12}\right|$
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