$\left(4a^2+3b^3\right)\left(4a^2-3b^3\right)$
$\left(y-yx^2\right)\frac{dy}{dx}=\left(y-1\right)$
$-2\cdot9-4$
$z^2+2z$
$y=-2\sin\left(\sqrt{4x^3+2}\right)$
$\int\frac{\left(x+3\right)}{\left(2x^3-8x\right)}dx$
$6\cos\left(2x\right)\:-\:3\:=0$
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