$\left(5abc-5bcd\right)^3$
$\frac{1}{x^4+4x^2+4}$
$35m^5-49^3$
$\left(w^5m^3\right)^2$
$\lim_{x\to1}\left(x^{\frac{1}{x^2-1}}\right)$
$\lim_{x\to a}\left(\frac{x^4-1}{x^3-1}\right)$
$4p+9f=60$
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