$6\left(8x+3\right)=-22+8x$
$-7\cdot0.28$
$1+sec^2a=2tan^2a+3$
$\int\left(3+x^2\right)\sqrt{5+4x}dx$
$\left(3a^3+5b^2\right)\left(3a^3-3b^8\right)$
$\lim_{x\to-1}\left(\frac{\ln\left(2x+3\right)}{x+2}\right)$
$6x^2-10x-4$
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