$\int\left(2x\sqrt{x^2+3}\right)dx$
$\left(2x^5+3x^2\right)^3$
$6x-\left(-3x\right)+x-6$
$\left(y\:n\:b\:7\right)^2$
$\left(\frac{1}{3}y\right)\left(-\frac{1}{3}y\right)$
$\frac{dy}{dx}=\frac{x+y}{1-x-y}$
$\int\:\frac{1}{\:9x^2-16}dx$
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