$\left(4\sqrt{2x+3}\right)^2$
$\frac{8}{\frac{x}{2}}$
$2y'+\:y\:=\:0$
$\frac{\tan^2\left(x\right)+1}{1-\sin^2\left(x\right)}$
$\left(-6x^4+5x^3\right)\left(-6x^4-5x^3\right)$
$\sec\frac{x}{2}\:+2=0$
$447.2133^2$
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