$\left(3x-12\right)\left(x+4\right)=3\left(x^2-8x+16\right)$
$15x+10y$
$\frac{x^2-9x+8}{3x^2-24x}.\frac{4x^3}{x^2-1}$
$\left(-5-7+4\right)-\left(8+3-9\right)$
$3x\left(x-3\right)>3x^2$
$2^3-3^2-4$
$\frac{1}{cot\infty}=sin\infty sec\infty$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!