$f\left(x\right)=\ln\left(\sec\left(x\right)+\tan\left(x\right)\right)$
$\frac{4xy^2z}{2x^4y}$
$\frac{dy}{dx}=\frac{-sen2x+2xy^2}{2y\left(1-x^2\right)}$
$4b\:2\:x\:4b\:2\:$
$3y^6\:and\:6y^2$
$\left(\frac{26}{2}\right)^2$
$0 < 4 n + 1$
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