$12x^2-13-35$
$x ^ { 2 } y - 2 y = x ^ { 3 } - 1$
$y=\left(4x\right)^{x+9}$
$4x^212x+9$
$\frac{n^{4}+2n^{2}-48}{n^{2}+8}$
$\lim_{x\to\infty}\left(1+\frac{12}{x}\right)^{\frac{x}{4}}$
$x^2\le2x-9$
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