$2y-5=25$
$\left(x^2-4\right)\left(3x-5\right)$
$8y^2+40y+50$
$\left(8\right)-\left(-25\right)$
$+1a^2-3a+3a-9$
$\csc\left(2x\right)=\:\frac{\sec\left(x\right)}{2\sin\left(x\right)}$
$\cos x+\sin x\tan x=7$
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