$\frac{d^3}{dx^3}\:in\left(\:sen\:x\right)$
$7\left(y-3\right)-3y+6$
$n^4+10^2\:p+25\:p^2$
$12x^2-18x+9^2$
$\frac{3}{x-4}+\frac{3}{x+4}=\frac{24}{x^2-16}$
$-6\left(3\right)\left(-1\right)\left(-1\right)$
$\frac{dp}{dt}=\frac{1}{p}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!