$\frac{1+cot\left(x\right)}{1+tan\left(x\right)}=cot\left(x\right)$
$\left(3x^2\right)\left(6x^2y+2x\right)$
$y=\frac{1}{x}+\frac{1}{x^2}$
$\lim_{x\to0}\left(tan\left(4x\right)\right)^x$
$\frac{4n^2-7n^2+n^2}{2n+1}$
$50+x\:=30$
$25x^2\:9y^2$
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